(C) The number of half-lives $(n)$ is calculated as $n = \frac{\text{Total time}}{\text{Half-life}} = \frac{100 \ min}{25 \ min} = 4$. The amount rema

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(C) The number of half-lives $(n)$ is calculated as $n = \frac{\text{Total time}}{\text{Half-life}} = \frac{100 \ min}{25 \ min} = 4$. The amount remaining $(N)$ is given by the formula $N = \frac{N_0}{2^n}$,where $N_0$ is the initial amount. Substituting the values,$N = \frac{100 \ g}{2^4} = \frac{100 \ g}{16} = 6.25 \ g$.

Class 12 Chemistry Nuclear Chemistry Rate of decay and Half-life

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$A$ certain nuclide has a half-life of $25 \ min$. If one starts with $100 \ g$ of it,how much of it will remain at the end of $100 \ min$?

A
$1.0$
B
$4.0$
C
$6.25$
D
$12.50$

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Nuclear Chemistry

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Rate of decay and Half-life

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$A$ certain nuclide has a half-life of $25 \ min$. If one starts with $100 \ g$ of it,how much of it will remain at the end of $100 \ min$?

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