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(B) According to Gauss's Law,the total electric flux through a closed surface is $\frac{Q}{\varepsilon_0}$.To calculate the flux through the square su

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$\frac{Q}{6\varepsilon_0}$

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(B) According to Gauss's Law,the total electric flux through a closed surface is $\frac{Q}{\varepsilon_0}$.To calculate the flux through the square surface of edge $a$,we can imagine this square as one face of a cube of side $a$.Since the charge $Q$ is placed at a distance $a/2$ above the centre of the square,it is exactly at the centre of this imaginary cube.By symmetry,the total electric flux $\frac{Q}{\varepsilon_0}$ is distributed equally among the $6$ faces of the cube.Therefore,the electric flux through the given square surface is $\frac{1}{6}$ of the total flux.Flux through the square surface = $\frac{Q}{6\varepsilon_0}$.

$A$ charge $Q$ is placed at a distance $a/2$ above the centre of the square surface of edge $a$ as shown in the figure. The electric flux through the square surface is

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