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Question

(D) When a charged particle enters a magnetic field perpendicular to its direction of motion,it experiences a magnetic Lorentz force $F = q(v 	imes B

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the momentum changes but the kinetic energy is constant

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(D) When a charged particle enters a magnetic field perpendicular to its direction of motion,it experiences a magnetic Lorentz force $F = q(v 	imes B)$.Since the force is always perpendicular to the velocity,it acts as a centripetal force,causing the particle to move in a circular path.In uniform circular motion,the magnitude of velocity (speed) remains constant,so the kinetic energy $K = \frac{1}{2}mv^2$ remains constant.However,the direction of the velocity vector changes continuously at every point along the circular path.Since momentum $p = mv$ is a vector quantity,a change in the direction of velocity implies a change in the momentum vector.Therefore,the momentum changes while the kinetic energy remains constant.

$A$ charged particle moves through a magnetic field perpendicular to its direction. Then

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