A circular ground whose diameter is 35 m has | vedclass

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(A) The diameter of the circular ground is $35 \ m$,so the radius of the ground $(r)$ is $35 / 2 = 17.5 \ m$.The garden is $1.4 \ m$ broad around the

Vedclass · Accepted Answer

$160.16$

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(A) The diameter of the circular ground is $35 \ m$,so the radius of the ground $(r)$ is $35 / 2 = 17.5 \ m$.The garden is $1.4 \ m$ broad around the ground,so the radius of the outer circle $(R)$ is $17.5 + 1.4 = 18.9 \ m$.The area of the garden is the difference between the area of the outer circle and the area of the inner circular ground.Area of garden $= \pi R^2 - \pi r^2 = \pi (R^2 - r^2) = \pi (R + r)(R - r)$.Area of garden $= \frac{22}{7} 	imes (18.9 + 17.5) 	imes (18.9 - 17.5)$.Area of garden $= \frac{22}{7} 	imes 36.4 	imes 1.4$.Area of garden $= 22 	imes 36.4 	imes 0.2 = 22 	imes 7.28 = 160.16 \ m^2$.

$A$ circular ground whose diameter is $35 \ m$ has a $1.4 \ m$ broad garden around it. What is the area of the garden in square metres?

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