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(B) Let the radius of the inner circle be $r$ and the radius of the outer circle be $R$.Let the uniform width of the path be $x$.Then,$R = r + x$,whic

Vedclass · Accepted Answer

$21$

Vedclass · Answer

(B) Let the radius of the inner circle be $r$ and the radius of the outer circle be $R$.Let the uniform width of the path be $x$.Then,$R = r + x$,which implies $R - r = x$.The difference between the outer and inner circumferences is given by $2 \pi R - 2 \pi r = 132 \, m$.Factoring out $2 \pi$,we get $2 \pi (R - r) = 132$.Since $R - r = x$,the equation becomes $2 \pi x = 132$.Substituting $\pi = \frac{22}{7}$,we have $2 	imes \frac{22}{7} 	imes x = 132$.Solving for $x$: $x = \frac{132 	imes 7}{2 	imes 22} = \frac{132 	imes 7}{44} = 3 	imes 7 = 21 \, m$.Therefore,the width of the path is $21 \, m$.

$A$ circular park has a path of uniform width around it. The difference between the outer and inner circumferences of the circular path is $132 \, m$. Its width is.....$m$.

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