A tank is 25 m long,12 m wide and 6 m deep | vedclass

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Question

(C) The tank is an open cuboid. The area to be plastered includes the four walls and the bottom.Area of four walls $= 2(length + width) 	imes height

Vedclass · Accepted Answer

$558$

Vedclass · Answer

(C) The tank is an open cuboid. The area to be plastered includes the four walls and the bottom.Area of four walls $= 2(length + width) 	imes height = 2(25 + 12) 	imes 6 = 2(37) 	imes 6 = 444 \ m^2$.Area of the bottom $= length 	imes width = 25 	imes 12 = 300 \ m^2$.Total surface area to be plastered $= 444 + 300 = 744 \ m^2$.Cost of plastering $= 744 	imes 0.75 \ Rs./m^2 = 744 	imes \frac{3}{4} = 186 	imes 3 = ₹ 558$.

$A$ tank is $25 \ m$ long,$12 \ m$ wide and $6 \ m$ deep. The cost of plastering its walls and bottom at $75 \ paise/m^2$ is (in $Rs.$)

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