$A$ coil carrying a heavy current and having a large number of turns is mounted in a $N-S$ vertical plane,and a current flows in a clockwise direction. $A$ small magnetic needle at its center will have its north pole in:

$A$ steady current $i$ flows in a small square loop of wire of side $L$ in a horizontal plane. The loop is now folded about its middle such that half of it lies in a vertical plane. Let $\overrightarrow {{\mu _1}} $ and $\overrightarrow {{\mu _2}} $ respectively denote the magnetic moments due to the current loop before and after folding. Then

The magnetic moment of a circular orbit of radius $r$ carrying a charge $q$ and rotating with velocity $v$ is given by

$A$ uniformly charged dielectric ring rotating with constant angular velocity $\omega$ about its geometrical axis produces:

$A$ current $i$ is flowing in a conductor of length $l$. When it is bent in the form of a circular loop,then its magnetic moment will be-

$A$ circular coil of area $2 \,cm^2$ has $1000$ turns. If the current through the coil is $1 \,A$, then its magnetic moment is (in $\,Am^2$)