$A$ coil has a resistance of $30\,\Omega$ and an inductive reactance of $20\,\Omega$ at a frequency of $50\,Hz$. If an $AC$ source of $200\,V$ and $100\,Hz$ is connected across the coil,the current in the coil will be.......$A$

$A$ series $R-C$ combination is connected to an $AC$ voltage of angular frequency $\omega = 500 \ rad/s$. If the impedance of the $R-C$ circuit is $R\sqrt{1.25}$,the time constant (in $ms$) of the circuit is:

$A$ coil has $L = 0.04 \, H$ and $R = 12 \, \Omega$. When it is connected to a $220 \, V$,$50 \, Hz$ supply,the current flowing through the coil in amperes is: (in $.7$)

When $100 \, V$ $DC$ is supplied across a solenoid,a current of $1.0 \, A$ flows in it. When $100 \, V$ $AC$ is applied across the same coil,the current drops to $0.5 \, A$. If the frequency of the $AC$ source is $50 \, Hz$,then the impedance and inductance of the solenoid are:

In an $L-R$ circuit,the inductive reactance is equal to $\sqrt{3}$ times the resistance $R$ of the circuit. An e.m.f. $E = E_0 \sin(\omega t)$ is applied to the circuit. The power consumed in the circuit is:

In the following circuit,an $AC$ input $V_i(t) = (20 \text{ mV}) \sin(10^5 t)$ is applied at the left end. The amplitude of the output voltage $V_0$ at the right end across the capacitor will be (in $mV$)