A compound M_pX_q has a cubic close packing ( | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In the given unit cell,$X$ atoms are at the corners and face centers,which is characteristic of a $ccp$ arrangement.Number of $X$ atoms = $8 	ime

Vedclass · Accepted Answer

$MX_2$

Vedclass · Answer

(B) In the given unit cell,$X$ atoms are at the corners and face centers,which is characteristic of a $ccp$ arrangement.Number of $X$ atoms = $8 	imes \frac{1}{8} (	ext{corners}) + 6 	imes \frac{1}{2} (	ext{face centers}) = 1 + 3 = 4$.$M$ atoms are located at the edges (specifically,there are $4$ $M$ atoms on the edges,each shared by $4$ unit cells) and one at the body center.Number of $M$ atoms = $4 	imes \frac{1}{4} (	ext{edges}) + 1 (	ext{body center}) = 1 + 1 = 2$.The ratio of $M:X$ is $2:4$,which simplifies to $1:2$.Therefore,the empirical formula is $MX_2$.

$A$ compound $M_pX_q$ has a cubic close packing $(ccp)$ arrangement of $X$. Its unit cell structure is shown below. The empirical formula of the compound is:
$M = \square$
$X = \bigcirc$

Similar Questions

Coordination number of $Na^{+}$ ion in rock salt is

In the rock salt structure,the $ccp$ arrangement of $Cl^{-}$ ions creates tetrahedral voids,which are....

Calculate the total volume occupied by all atoms in a simple cubic unit cell if the radius of the atom is $3 \times 10^{-8} \ cm$.

What is the number of unit cells in one mole of an atom of a metal that forms a simple cubic structure?

What is the coordination number of a cation occupying an octahedral void?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$A$ compound $M_pX_q$ has a cubic close packing $(ccp)$ arrangement of $X$. Its unit cell structure is shown below. The empirical formula of the compound is:$M = \square$$X = \bigcirc$