A compound A with molecular formula C_{10}H_{ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Compound $A$ $(C_{10}H_{13}Cl)$ gives a white precipitate with silver nitrate,indicating it is a tertiary halide or a reactive alkyl halide that f

Vedclass · Accepted Answer

$C_6H_5-CH_2-C(Cl)(CH_3)_2$

Vedclass · Answer

(C) Compound $A$ $(C_{10}H_{13}Cl)$ gives a white precipitate with silver nitrate,indicating it is a tertiary halide or a reactive alkyl halide that forms a stable carbocation.$C_6H_5-CH_2-C(Cl)(CH_3)_2 (A) \xrightarrow{alc. KOH} C_6H_5-CH=C(CH_3)_2 (B)$$B$ on ozonolysis:$C_6H_5-CH=C(CH_3)_2 \xrightarrow{O_3/H_2O} C_6H_5CHO (C) + CH_3COCH_3 (D)$$C$ $(C_6H_5CHO)$ has no $\alpha$-hydrogen,so it gives Cannizzaro reaction but not aldol condensation.$D$ $(CH_3COCH_3)$ has $\alpha$-hydrogens,so it gives aldol condensation but not Cannizzaro reaction.Thus,$A$ is $C_6H_5-CH_2-C(Cl)(CH_3)_2$.

Similar Questions

An organic compound $x$ where the molar ratio of $C$, $O$, and $H$ are equal, on treatment with $50\% \ KOH$ under reflux followed by acidification produced $y$. The most likely structure of $y$ is: [Molar mass of $x$ is $58 \ g \ mol^{-1}$]

For the reaction,the product expected is:

The product formed in the given reaction sequence is:

Which of the following reactants,on reaction with concentrated $NaOH$ followed by acidification,gives the following lactone as the product?

$CH_3CH=CHCHO$ is oxidized to $CH_3CH=CHCOOH$ using

Vedclass Test Series

Exam Paper Generator

Online Exam Module