For the reaction,the product expected is:

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(D) The reaction of phthalic anhydride with $2 	ext{ moles}$ of $CH_3MgBr$ (a Grignard reagent) proceeds as follows:$1$. The first equivalent of $CH_

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(D) The reaction of phthalic anhydride with $2 	ext{ moles}$ of $CH_3MgBr$ (a Grignard reagent) proceeds as follows:$1$. The first equivalent of $CH_3MgBr$ attacks one of the carbonyl carbons of the phthalic anhydride,opening the anhydride ring to form a magnesium salt of an ortho-acetylbenzoic acid derivative.$2$. The second equivalent of $CH_3MgBr$ attacks the newly formed ketone carbonyl group.$3$. Upon acidic workup with $H_3O^+$,the magnesium salts are protonated to yield $2-(2-	ext{hydroxypropan}-2-	ext{yl})	ext{benzoic acid}$ as the final product.

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