The reaction that does not give benzoic acid | vedclass

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(C) The oxidation of primary alcohols with strong oxidizing agents like $K_2Cr_2O_7$ or $KMnO_4/H^+$ yields carboxylic acids. Thus,phenylmethanol $(C_

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(C) The oxidation of primary alcohols with strong oxidizing agents like $K_2Cr_2O_7$ or $KMnO_4/H^+$ yields carboxylic acids. Thus,phenylmethanol $(C_6H_5CH_2OH)$ gives benzoic acid $(C_6H_5COOH)$ in options $A$ and $D$.The haloform reaction of acetophenone $(C_6H_5COCH_3)$ with $NaOCl$ followed by acid workup $(H_3O^+)$ is a standard method to produce benzoic acid,as shown in option $B$.$PCC$ (Pyridinium chlorochromate) is a mild oxidizing agent that oxidizes primary alcohols only up to the aldehyde stage. Therefore,the reaction of phenylmethanol with $PCC$ yields benzaldehyde $(C_6H_5CHO)$ as the major product,not benzoic acid. Hence,option $C$ is the correct answer.

Column-$I$ (Reactions)	Column-$II$ (Reagents)
$(i)$. Benzophenone $\rightarrow$ Diphenylmethane	$(a)$. $LiAlH_4$
$(ii)$. Benzaldehyde $\rightarrow$ $1-$Phenylethanol	$(b)$. $DIBAL-H$
$(iii)$. Cyclohexanone $\rightarrow$ Cyclohexanol	$(c)$. $Zn(Hg) / \text{Conc. } HCl$
$(iv)$. Phenyl benzoate $\rightarrow$ Benzaldehyde	$(d)$. $CH_3MgBr, H_2O$

The reaction that does not give benzoic acid as the major product is

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