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(D) The focal length of a lens in a medium is given by the Lens Maker's Formula:$\frac{1}{f} = \left( \frac{n_l}{n_m} - 1 \right) \left( \frac{1}{R_1}

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convergent lens of focal length $0.5 \, m$

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(D) The focal length of a lens in a medium is given by the Lens Maker's Formula:$\frac{1}{f} = \left( \frac{n_l}{n_m} - 1 ight) \left( \frac{1}{R_1} - \frac{1}{R_2} ight)$Given:Refractive index of lens material,$n_l = 1.6$Refractive index of medium,$n_m = 2.0$For a concave lens,$R_1 = -0.2 \, m$ and $R_2 = +0.2 \, m$.Substituting these values into the formula:$\frac{1}{f} = \left( \frac{1.6}{2.0} - 1 ight) \left( \frac{1}{-0.2} - \frac{1}{0.2} ight)$$\frac{1}{f} = (0.8 - 1) \left( -5 - 5 ight)$$\frac{1}{f} = (-0.2) 	imes (-10)$$\frac{1}{f} = 2$$f = 0.5 \, m$Since the focal length $f$ is positive,the lens behaves as a convergent lens with a focal length of $0.5 \, m$.

$A$ concave lens made of material of refractive index $1.6$ is immersed in a medium of refractive index $2.0$. The two surfaces of the concave lens have the same radius of curvature $0.2 \, m$. The lens will behave as a

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