A concave mirror of focal length 15, cm forms | vedclass

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(B) For a concave mirror,the focal length $f = -15\, cm$.Since the image is virtual,the magnification $m = +2$.Using the magnification formula $m = -\

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$7.5$

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(B) For a concave mirror,the focal length $f = -15\, cm$.Since the image is virtual,the magnification $m = +2$.Using the magnification formula $m = -\frac{v}{u}$,we get $2 = -\frac{v}{u}$,which implies $v = -2u$.Applying the mirror formula $\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$:$\frac{1}{-15} = \frac{1}{-2u} + \frac{1}{u}$$\frac{1}{-15} = \frac{-1 + 2}{2u}$$\frac{1}{-15} = \frac{1}{2u}$$2u = -15$$u = -7.5\, cm$.Thus,the object is placed at a distance of $7.5\, cm$ from the mirror.

$A$ concave mirror of focal length $15\, cm$ forms an image having twice the linear dimensions of the object. The position of the object when the image is virtual will be........$cm$

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