$A$ constant force acting on a body of mass $5\,kg$ changes its speed from $5\,ms^{-1}$ to $10\,ms^{-1}$ in $10\,s$ without changing the direction of motion. The force acting on the body is ......... $N$.

$A$ body of $5 \, kg$ is moving with a velocity of $20 \, m/s$. If a force of $100 \, N$ is applied on it for $10 \, s$ in the same direction as its velocity,what will be the final velocity of the body in $m/s$?

$A$ force vector applied on a mass is represented as $\vec{F} = 6\hat{i} - 8\hat{j} + 10\hat{k} \, N$ and it accelerates with $1 \, m/s^2$. What will be the mass of the body?

$A$ body of mass $4 \ kg$ experiences two forces $\overrightarrow{F}_1 = 5 \hat{i} + 8 \hat{j} + 7 \hat{k}$ and $\overrightarrow{F}_2 = 3 \hat{i} - 4 \hat{j} - 3 \hat{k}$. The acceleration acting on the body is :

$A$ person holds a ball of mass $0.25 \ kg$ in his hand and throws it,so that it leaves his hand with a speed of $12 \ m \ s^{-1}$. In this process,if his hand moved through a distance of $0.9 \ m$,then the net force acted on the ball is (in $N$)

$A$ body of mass $1.5 \ kg$ is moving towards south with a uniform velocity of $8 \ ms^{-1}$. $A$ force of $6 \ N$ is applied to the body towards east. The displacement of the body $3 \ s$ after the application of the force is (in $m$)