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Question

(A) For a constant volume gas thermometer,the temperature $t$ is related to pressure $P$ by the linear relation: $t = \frac{P_t - P_0}{P_{100} - P_0}

Vedclass · Accepted Answer

$25$

Vedclass · Answer

(A) For a constant volume gas thermometer,the temperature $t$ is related to pressure $P$ by the linear relation: $t = \frac{P_t - P_0}{P_{100} - P_0} 	imes 100^{\circ} C$. Given: $P_0 = 50 \, cm$ of Hg at $0^{\circ} C$,$P_{100} = 90 \, cm$ of Hg at $100^{\circ} C$,$P_t = 60 \, cm$ of Hg. Substituting these values into the formula: $t = \frac{60 - 50}{90 - 50} 	imes 100^{\circ} C$ $t = \frac{10}{40} 	imes 100^{\circ} C$ $t = \frac{1}{4} 	imes 100^{\circ} C = 25^{\circ} C$. Thus,the temperature is $25^{\circ} C$.

$A$ constant volume gas thermometer shows pressure readings of $50 \, cm$ and $90 \, cm$ of mercury at $0^{\circ} C$ and $100^{\circ} C$ respectively. When the pressure reading is $60 \, cm$ of mercury,the temperature is ......... $^{\circ} C$.

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