A container contains 50 , text{litres} of mil | vedclass

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(D) The formula for the quantity of milk remaining after $n$ operations is given by:$	ext{Remaining Milk} = x \left(1 - \frac{y}{x}ight)^n$Where:$x

Vedclass · Accepted Answer

$36.45$

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(D) The formula for the quantity of milk remaining after $n$ operations is given by:$	ext{Remaining Milk} = x \left(1 - \frac{y}{x}ight)^n$Where:$x = 50 \, 	ext{litres}$ (initial quantity of milk)$y = 5 \, 	ext{litres}$ (quantity replaced in each operation)$n = 3$ (total number of operations,as the process was repeated two more times after the first)Substituting the values:$	ext{Remaining Milk} = 50 \left(1 - \frac{5}{50}ight)^3$$= 50 \left(1 - \frac{1}{10}ight)^3$$= 50 \left(\frac{9}{10}ight)^3$$= 50 	imes \frac{729}{1000}$$= \frac{729}{20} = 36.45 \, 	ext{litres}$

$A$ container contains $50 \, \text{litres}$ of milk. From this container $5 \, \text{litres}$ of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container? (in $\text{litres}$)

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