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(A) The container consists of a cylinder and a hemisphere. Radius of the cylinder $(r)$ = $8.4 \,cm$. Radius of the hemisphere $(r)$ = $8.4 \,cm$. Tot

Vedclass · Accepted Answer

$11.088$

Vedclass · Answer

(A) The container consists of a cylinder and a hemisphere. Radius of the cylinder $(r)$ = $8.4 \,cm$. Radius of the hemisphere $(r)$ = $8.4 \,cm$. Total height of the container $(H)$ = $52.8 \,cm$. Height of the cylinder $(h)$ = $H - r = 52.8 - 8.4 = 44.4 \,cm$. Volume of the container = Volume of cylinder + Volume of hemisphere. Volume = $\pi r^2 h + \frac{2}{3} \pi r^3 = \pi r^2 (h + \frac{2}{3} r)$. Volume = $\frac{22}{7} 	imes (8.4)^2 	imes (44.4 + \frac{2}{3} 	imes 8.4)$. Volume = $\frac{22}{7} 	imes 70.56 	imes (44.4 + 5.6) = \frac{22}{7} 	imes 70.56 	imes 50$. Volume = $22 	imes 10.08 	imes 50 = 11088 \,cm^3$. Since $1000 \,cm^3 = 1 \,litre$,the volume in litres = $11088 / 1000 = 11.088 \,litres$.

$A$ container is in the form of a cylinder closed at one end by a hemisphere. The radius of the cylinder is $8.4 \,cm$ and the total height of the container is $52.8 \,cm$. How many litres of petrol can this container hold? (in $litres$)

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