$A$ copper wire of resistance $R$ is cut into ten parts of equal length. Two pieces each are joined in series and then five such combinations are joined in parallel. The new combination will have a resistance

  • A
    $R$
  • B
    $\frac{R}{4}$
  • C
    $\frac{R}{5}$
  • D
    $\frac{R}{25}$

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