A cubical ice cream brick of edge 22 , cm is | vedclass

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(C) The volume of the cubical ice cream brick is given by $V_{cube} = a^3$,where $a = 22 \, cm$.$V_{cube} = 22 	imes 22 	imes 22 = 10648 \, cm^3$.Th

Vedclass · Accepted Answer

$363$

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(C) The volume of the cubical ice cream brick is given by $V_{cube} = a^3$,where $a = 22 \, cm$.$V_{cube} = 22 	imes 22 	imes 22 = 10648 \, cm^3$.The volume of one ice cream cone is given by $V_{cone} = \frac{1}{3} \pi r^2 h$,where $r = 2 \, cm$ and $h = 7 \, cm$.Using $\pi = \frac{22}{7}$,we get $V_{cone} = \frac{1}{3} 	imes \frac{22}{7} 	imes 2^2 	imes 7 = \frac{1}{3} 	imes 22 	imes 4 = \frac{88}{3} \, cm^3$.The number of children who will get the ice cream is the total volume of the brick divided by the volume of one cone.Number of children $= \frac{V_{cube}}{V_{cone}} = \frac{10648}{88/3} = \frac{10648 	imes 3}{88}$.$10648 \div 88 = 121$.Number of children $= 121 	imes 3 = 363$.

$A$ cubical ice cream brick of edge $22 \, cm$ is to be distributed among some children by filling ice cream cones of radius $2 \, cm$ and height $7 \, cm$ up to its brim. How many children will get the ice cream cones?

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