A rectangular water tank of base 11 ,m times | vedclass

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(B) Given,dimensions of the base of the rectangular tank $= 11 \,m 	imes 6 \,m$ and the height of water $= 5 \,m$.Volume of the water in the rectangu

Vedclass · Accepted Answer

$8.6$

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(B) Given,dimensions of the base of the rectangular tank $= 11 \,m 	imes 6 \,m$ and the height of water $= 5 \,m$.Volume of the water in the rectangular tank $= 11 	imes 6 	imes 5 = 330 \,m^3$.Also,the radius of the cylindrical tank is given as $r = 3.5 \,m$.Let the height of the water level in the cylindrical tank be $h$. The volume of water in the cylindrical tank is given by the formula $V = \pi r^2 h$.$V = \frac{22}{7} 	imes (3.5)^2 	imes h = \frac{22}{7} 	imes 3.5 	imes 3.5 	imes h = 22 	imes 0.5 	imes 3.5 	imes h = 38.5 h \,m^3$.Since the volume of water remains the same when transferred:$38.5 h = 330$.$h = \frac{330}{38.5} = \frac{3300}{385} \approx 8.571 \,m$.Rounding to one decimal place,the height of the water level is $8.6 \,m$.

$A$ rectangular water tank of base $11 \,m \times 6 \,m$ contains water up to a height of $5 \,m$. If the water in the tank is transferred to a cylindrical tank of radius $3.5 \,m$,find the height of the water level in the tank. (in $m$)

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