A dice is thrown twice. The probability of ge | vedclass

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(B) Let $A$ be the event of getting $4, 5$ or $6$ in the first throw. The total outcomes for a single throw are $6$. The favorable outcomes are ${4, 5

Vedclass · Accepted Answer

$\frac{1}{3}$

Vedclass · Answer

(B) Let $A$ be the event of getting $4, 5$ or $6$ in the first throw. The total outcomes for a single throw are $6$. The favorable outcomes are ${4, 5, 6}$,so the number of favorable outcomes is $3$.$P(A) = \frac{3}{6} = \frac{1}{2}$.Let $B$ be the event of getting $1, 2, 3$ or $4$ in the second throw. The favorable outcomes are ${1, 2, 3, 4}$,so the number of favorable outcomes is $4$.$P(B) = \frac{4}{6} = \frac{2}{3}$.Since the two throws are independent events,the probability of both events occurring is $P(A \cap B) = P(A) 	imes P(B)$.$P(A \cap B) = \frac{1}{2} 	imes \frac{2}{3} = \frac{2}{6} = \frac{1}{3}$.

$A$ dice is thrown twice. The probability of getting $4, 5$ or $6$ in the first throw and $1, 2, 3$ or $4$ in the second throw is

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