In a single throw of 3 dice,find the probabil | vedclass

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(C) The total number of possible outcomes when throwing $3$ dice is $6 	imes 6 	imes 6 = 216$.We need to find the number of outcomes where the sum o

Vedclass · Accepted Answer

$\frac{1}{36}$

Vedclass · Answer

(C) The total number of possible outcomes when throwing $3$ dice is $6 	imes 6 	imes 6 = 216$.We need to find the number of outcomes where the sum of the numbers on the $3$ dice is $5$.The possible combinations are:$(1, 1, 3)$ which can be arranged in $3$ ways: $(1, 1, 3), (1, 3, 1), (3, 1, 1)$.$(1, 2, 2)$ which can be arranged in $3$ ways: $(1, 2, 2), (2, 1, 2), (2, 2, 1)$.Total favorable outcomes $= 3 + 3 = 6$.Therefore,the probability $P = \frac{	ext{Number of favorable outcomes}}{	ext{Total number of outcomes}} = \frac{6}{216} = \frac{1}{36}$.

In a single throw of $3$ dice,find the probability of getting a total of $5$.

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