$A$ die is loaded in such a way that each odd number is twice as likely to occur as each even number. If $E$ is the event that a number greater than or equal to $4$ occurs on a single toss of the die,then $P(E)$ is equal to:

  • A
    $\frac{4}{9}$
  • B
    $\frac{2}{3}$
  • C
    $\frac{1}{3}$
  • D
    $\frac{1}{2}$

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