$A$ die is thrown $1000$ times and the outcomes were recorded as follows:
Outcome $1$ $2$ $3$ $4$ $5$ $6$
Frequency $180$ $150$ $160$ $170$ $150$ $190$

If the die is thrown once more,then the probability that it shows $5$ is:

  • A
    $9/50$
  • B
    $4/25$
  • C
    $3/20$
  • D
    $7/25$

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Similar Questions

The marks obtained (out of $25$ marks) by $40$ students in an examination are as given below:
$\begin{array}{rrrrrrrrrr} 8, & 12, & 23, & 9, & 5, & 20, & 16, & 3, & 6, & 23 \\ 10, & 6, & 21, & 1, & 18, & 17, & 18, & 16, & 16, & 12, \\ 3, & 15, & 21, & 7, & 12, & 5, & 2, & 7, & 13, & 24, \\ 13, & 18, & 8, & 2, & 20, & 5, & 13, & 7, & 23, & 16 \end{array}$
Represent the data given above by a grouped frequency distribution table,taking the class intervals as $0-5, 5-10, \dots$ etc.

The weights (in $kg$) of $11$ students are given below:
$37, 42, 40, 39, 41, 35, 37, 36, 40, 40, 42$
Find the median of the data.

The following table gives the distribution of students of sections $A$ and $B$ of a class according to the marks obtained by them.
Marks Section $A$ Frequency Section $B$ Frequency
$0-15$ $3$ $3$
$15-30$ $12$ $16$
$30-45$ $28$ $25$
$45-60$ $30$ $27$
$60-75$ $35$ $40$
$75-90$ $13$ $10$

Represent the marks of the students of both the sections on the same graph by two frequency polygons. What do you observe?

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The mean of five numbers is $30$. If one number is excluded,their mean becomes $28$. The excluded number is:

If each observation of the data is increased by $5,$ then their mean

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