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Question

(A) The net potential at any point on the surface of an uncharged conducting sphere is equal to the potential due to the induced charges plus the pote

Vedclass · Accepted Answer

$\frac{kp \cos \phi}{r^2}$

Vedclass · Answer

(A) The net potential at any point on the surface of an uncharged conducting sphere is equal to the potential due to the induced charges plus the potential due to the external dipole.Since the sphere is uncharged and isolated,the total potential due to the induced charges on the surface of the sphere is zero at all points.Therefore,the net potential at point $A$ is simply the potential due to the dipole at that point.The potential $V$ due to a dipole with dipole moment $p$ at a distance $r$ and angle $\phi$ (where $\phi$ is the angle between the dipole moment vector and the position vector of the point) is given by:$V = \frac{kp \cos \phi}{r^2}$Thus,the net potential at point $A$ is $\frac{kp \cos \phi}{r^2}$.

$A$ dipole having dipole moment $p$ is placed in front of a solid uncharged conducting sphere as shown in the diagram. The net potential at point $A$ lying on the surface of the sphere is:

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