A drawer contains 50 bolts and 150 nuts. Half | vedclass

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(C) Total items $= 50 + 150 = 200$.Number of rusted bolts $= 50 / 2 = 25$.Number of rusted nuts $= 150 / 2 = 75$.Total rusted items $= 25 + 75 = 100$.

Vedclass · Accepted Answer

$5/8$

Vedclass · Answer

(C) Total items $= 50 + 150 = 200$.Number of rusted bolts $= 50 / 2 = 25$.Number of rusted nuts $= 150 / 2 = 75$.Total rusted items $= 25 + 75 = 100$.Let $A$ be the event of choosing a rusted item and $B$ be the event of choosing a bolt.$P(A) = 100 / 200 = 1/2$.$P(B) = 50 / 200 = 1/4$.$P(A \cap B)$ is the probability of choosing a rusted bolt,which is $25 / 200 = 1/8$.Using the addition rule of probability: $P(A \cup B) = P(A) + P(B) - P(A \cap B)$.$P(A \cup B) = 100/200 + 50/200 - 25/200 = 125/200 = 5/8$.

$A$ drawer contains $50$ bolts and $150$ nuts. Half of the bolts and half of the nuts are rusted. If $1$ item is chosen at random,what is the probability that it is rusted or is a bolt?

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