A driver of a train travelling at 40 , m s^{- | vedclass

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(A) Given: Initial velocity $u = 40 \, m s^{-1}$,Final velocity $v = 0 \, m s^{-1}$,Acceleration $a = -2 \, m s^{-2}$.Using the third equation of moti

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Yes,it stops exactly at the end of the platform.

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(A) Given: Initial velocity $u = 40 \, m s^{-1}$,Final velocity $v = 0 \, m s^{-1}$,Acceleration $a = -2 \, m s^{-2}$.Using the third equation of motion: $v^{2} = u^{2} + 2aS$.Substituting the values: $0^{2} = (40)^{2} + 2(-2)S$.$0 = 1600 - 4S$.$4S = 1600$.$S = 400 \, m$.Since the calculated stopping distance is $400 \, m$ and the platform length is $400 \, m$,the train will stop exactly at the end of the platform.

$A$ driver of a train travelling at $40 \, m s^{-1}$ applies the brakes as the train enters a station. The train slows down at a rate of $2 \, m s^{-2}$. The platform is $400 \, m$ long. Will the train stop in time?

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