(A) The angular momentum $L$ of a rotating body is given by the formula $L = I\omega$,where $I$ is the moment of inertia and $\omega$ is the angular v

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(A) The angular momentum $L$ of a rotating body is given by the formula $L = I\omega$,where $I$ is the moment of inertia and $\omega$ is the angular velocity.Given:$I = 0.6 \,kg \cdot m^2$Frequency $f = 0.5 \,rev/s$The angular velocity $\omega$ is related to frequency by $\omega = 2\pi f$.Substituting the values:$\omega = 2 \times \pi \times 0.5 = \pi \,rad/s$.Now,calculating the angular momentum:$L = 0.6 \times \pi = 0.6\pi \,kg \cdot m^2/s$.

Class 11 Physics System of Particles and Rotational Motion Angular Momentum and Angular Impulse

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$A$ fan of moment of inertia $0.6\,kg \cdot m^2$ is turned up to a working speed of $0.5$ revolutions per second. The angular momentum of the fan is:

A
$0.6\pi \,kg \cdot m^2/s$
B
$6\,kg \cdot m^2/s$
C
$3\,kg \cdot m^2/s$
D
$\frac{\pi}{6} \,kg \cdot m^2/s$

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System of Particles and Rotational Motion

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Angular Momentum and Angular Impulse

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Two bodies rotate with kinetic energies $E_1$ and $E_2$. Their moments of inertia about their axes of rotation are $I_1$ and $I_2$. If $I_1 = \frac{I_2}{3}$ and $E_1 = 27 E_2$,then the ratio of their angular momenta $L_1$ to $L_2$ is:

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$A$ particle is moving in a circular path of radius $a$ with a constant speed $v$ as shown in the figure. The centre of the circle is marked by $C$. The angular momentum about the origin $O$ can be written as:

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$A$ fan of moment of inertia $0.6\,kg \cdot m^2$ is turned up to a working speed of $0.5$ revolutions per second. The angular momentum of the fan is:

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$A$ thin horizontal disc is rotating about a vertical axis passing through its fixed centre $O$. Its angular momentum is $L_A$ and $L_B$ computed about points $A$ and $B$, respectively, with $OB = 2 \times OA$. The value of $\frac{L_A}{L_B}$ is :

Two bodies rotate with kinetic energies $E_1$ and $E_2$. Their moments of inertia about their axes of rotation are $I_1$ and $I_2$. If $I_1 = \frac{I_2}{3}$ and $E_1 = 27 E_2$,then the ratio of their angular momenta $L_1$ to $L_2$ is:

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