A force vec F = 3hat i + chat j + 2hat k acti | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The work done $W$ by a force $\vec F$ during a displacement $\vec S$ is given by the dot product: $W = \vec F \cdot \vec S$.Given $\vec F = 3\hat

Vedclass · Accepted Answer

$12$

Vedclass · Answer

(A) The work done $W$ by a force $\vec F$ during a displacement $\vec S$ is given by the dot product: $W = \vec F \cdot \vec S$.Given $\vec F = 3\hat i + c\hat j + 2\hat k$ and $\vec S = -4\hat i + 2\hat j - 3\hat k$.Substituting these into the formula: $W = (3\hat i + c\hat j + 2\hat k) \cdot (-4\hat i + 2\hat j - 3\hat k)$.Calculating the dot product: $W = (3)(-4) + (c)(2) + (2)(-3) = -12 + 2c - 6 = 2c - 18$.Given that the work done $W = 6 \ J$,we set up the equation: $2c - 18 = 6$.Adding $18$ to both sides: $2c = 24$.Dividing by $2$: $c = 12$.

$A$ force $\vec F = 3\hat i + c\hat j + 2\hat k$ acting on a particle causes a displacement $\vec S = - 4\hat i + 2\hat j - 3\hat k$. If the work done is $6 \ J$,then the value of $c$ will be:

Similar Questions

When a force of $50 \, N$ is applied to an object,it undergoes a displacement of $10 \, m$ at an angle of $60^\circ$ with the direction of the force. The work done is ......... $J$.

The kinetic energy $(KE)$ acquired by a mass $m$ in travelling a certain distance $d$,starting from rest,under the action of a constant force $F$ is ..........

$A$ body of mass $50 \ kg$ is lifted to a height of $20 \ m$ from the ground in two different ways as shown in the figure. The ratio of work done against gravity in both the respective cases will be:

$A$ heavy object and a light object are placed on the same surface. If the same force is applied to both for the same displacement,on which object is more work done by the force?

Explain work done by a constant force.

Vedclass Test Series

Exam Paper Generator

Online Exam Module