A gene locus has two alleles A and a. If the | vedclass

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(C) According to the Hardy-Weinberg principle,the sum of allele frequencies is $p + q = 1$,where $p$ is the frequency of allele $A$ and $q$ is the fre

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$0.16(AA); 0.48(Aa); 0.36(aa)$

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(C) According to the Hardy-Weinberg principle,the sum of allele frequencies is $p + q = 1$,where $p$ is the frequency of allele $A$ and $q$ is the frequency of allele $a$.Given $p = 0.4$,then $q = 1 - 0.4 = 0.6$.The genotype frequencies are given by the expansion of $(p + q)^2 = p^2 + 2pq + q^2 = 1$.Here,$p^2$ represents the frequency of homozygous dominant individuals $(AA)$,$2pq$ represents the frequency of heterozygous individuals $(Aa)$,and $q^2$ represents the frequency of homozygous recessive individuals $(aa)$.Calculating the values:$p^2 = (0.4)^2 = 0.16 (AA)$$2pq = 2 	imes 0.4 	imes 0.6 = 0.48 (Aa)$$q^2 = (0.6)^2 = 0.36 (aa)$Therefore,the frequencies are $0.16(AA), 0.48(Aa),$ and $0.36(aa)$.

$A$ gene locus has two alleles $A$ and $a$. If the frequency of the dominant allele $A$ is $0.4$,then what will be the frequency of homozygous dominant,heterozygous,and homozygous recessive individuals in the population?

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