Frequency of heterozygous gene in Hardy-Weinb | vedclass

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(C) In the Hardy-Weinberg principle,the equation is given by $(p + q)^2 = p^2 + 2pq + q^2 = 1$.Here,$p$ represents the frequency of the dominant allel

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$2pq$

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(C) In the Hardy-Weinberg principle,the equation is given by $(p + q)^2 = p^2 + 2pq + q^2 = 1$.Here,$p$ represents the frequency of the dominant allele and $q$ represents the frequency of the recessive allele.$p^2$ represents the frequency of homozygous dominant individuals.$q^2$ represents the frequency of homozygous recessive individuals.$2pq$ represents the frequency of heterozygous individuals.Therefore,the frequency of the heterozygous gene is represented by $2pq$.

Frequency of heterozygous gene in Hardy-Weinberg principle is represented by . . . . . . .

Similar Questions

In a population that is in Hardy-Weinberg equilibrium,the frequency of the recessive allele for a certain genetic trait is $0.20$. What percentage of individuals in the next generation is expected to show the dominant trait (in $\%$)?

Which of the following processes affects the $Hardy-Weinberg$ principle to induce variation at the genetic level?

Recessive alleles are not lost from the gene pool. This is known as:

If $51\%$ of the members in a population possess at least one recessive allele,find the frequency of the dominant phenotype.

In the Hardy-Weinberg equation,the frequency of heterozygous individuals is represented by:

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