A glass rod of radius 1.0,mm is inserted symm | vedclass

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(C) The effective radius of the annular space between the glass rod and the capillary tube is given by the difference in their radii: $r_{eff} = r_2 -

Vedclass · Accepted Answer

$15$

Vedclass · Answer

(C) The effective radius of the annular space between the glass rod and the capillary tube is given by the difference in their radii: $r_{eff} = r_2 - r_1 = 2.0\,mm - 1.0\,mm = 1.0\,mm = 1.0 	imes 10^{-3}\,m$.Using the formula for capillary rise in an annular space: $h = \frac{2T}{ho g r_{eff}}$.Substituting the given values: $T = 75 	imes 10^{-3}\,N/m$,$ho = 10^3\,kg/m^3$,$g = 10\,m/s^2$,and $r_{eff} = 1.0 	imes 10^{-3}\,m$.$h = \frac{2 	imes 75 	imes 10^{-3}}{10^3 	imes 10 	imes 1.0 	imes 10^{-3}} = \frac{150 	imes 10^{-3}}{10} = 15 	imes 10^{-3}\,m$.Converting to millimeters: $h = 15\,mm$.

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