When a capillary tube is dipped vertically in water,the rise of water in the capillary is $h$. The angle of contact is $0^{\circ}$. Now,the tube is depressed so that its length above the water surface is $\frac{h}{3}$. The new apparent angle of contact is $(\cos 0^{\circ} = 1)$.

• A
  $\cos ^{-1}\left(\frac{1}{2}\right)$
• B
  $\cos ^{-1}\left(\frac{1}{3}\right)$
• C
  $\cos ^{-1}\left(\frac{1}{4}\right)$
• D
  $\cos ^{-1}\left(\frac{1}{6}\right)$