$A$ capillary tube made of glass is dipped into mercury. Then

When one end of a capillary tube is dipped in water,the height of water column is $h$. The upward force of $105 \text{ dyne}$ due to surface tension is balanced by the force due to the weight of water column. The inner circumference of the capillary tube is (Surface tension of water $= 7 \times 10^{-2} \text{ N/m}$) (in $\text{ cm}$)

$A$ capillary tube of radius $R$ is immersed in water and water rises in it to a height $H$. The mass of water in the capillary tube is $M$. If the radius of the tube is halved,the mass of water that will rise in the capillary tube will now be

The angle of contact between glass and water is $0^{\circ}$ and water rises in a glass capillary up to $6 \ cm$ (Surface tension of water is $T$). Another liquid of surface tension $2T$,angle of contact $60^{\circ}$ and relative density $2$ will rise in the same capillary up to (Given: $\cos 0^{\circ}=1, \cos 60^{\circ}=0.5$) (in $cm$)

$A$ long capillary tube of mass $\pi \,g$,radius $2\,mm$ and negligible thickness,is partially immersed in a liquid of surface tension $0.1\,N/m$. Take the angle of contact as zero and neglect the buoyant force of the liquid. Find the force required to hold the tube vertically. $(g = 10\,m/s^2)$

When a capillary is dipped in water,water rises to a height $h$. If the length of the capillary is made less than $h$,then