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(B) $1$. Calculate the maximum line-of-sight distance for space wave communication: $d_m = \sqrt{2Rh} = \sqrt{2 	imes 6.4 	imes 10^6 	imes 300} = \

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Sky wave propagation

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(B) $1$. Calculate the maximum line-of-sight distance for space wave communication: $d_m = \sqrt{2Rh} = \sqrt{2 	imes 6.4 	imes 10^6 	imes 300} = \sqrt{3840 	imes 10^6} \approx 61.97\, km \approx 62\, km$.$2$. Since the distance between the transmitter and receiver is $100\, km$,which is greater than $d_m$ $(100\, km > 62\, km)$,space wave propagation is not possible.$3$. Calculate the critical frequency of the ionosphere: $f_c = 9(N_{\max})^{1/2} = 9 	imes (10^{12})^{1/2} = 9 	imes 10^6\, Hz = 9\, MHz$.$4$. Since the signal frequency $(5\, MHz)$ is less than the critical frequency $(9\, MHz)$,the signal can be reflected by the ionosphere.$5$. Therefore,the signal is received via sky wave propagation.

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