The total power content of an AM wave is 1500 | vedclass

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(D) The total power of an $AM$ wave is given by the formula: $P_t = P_c (1 + \frac{m^2}{2})$,where $P_t$ is the total power,$P_c$ is the carrier power

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$1000$

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(D) The total power of an $AM$ wave is given by the formula: $P_t = P_c (1 + \frac{m^2}{2})$,where $P_t$ is the total power,$P_c$ is the carrier power,and $m$ is the modulation index.Given: $P_t = 1500 \, W$ and $m = 100 \% = 1$.Substituting the values into the formula: $1500 = P_c (1 + \frac{1^2}{2})$.$1500 = P_c (1 + 0.5) = P_c (1.5)$.$P_c = \frac{1500}{1.5} = 1000 \, W$.Therefore,the power transmitted by the carrier is $1000 \, W$.

The total power content of an $AM$ wave is $1500 \, W$. For $100 \%$ modulation,the power transmitted by the carrier is ........ $W$.

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