A hockey ball of mass 200 ,g travelling at 10 | vedclass

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Question

(B) Mass of the hockey ball,$m = 200 \,g = 0.2 \,kg$.Initial velocity of the hockey ball,$u = 10 \,m \,s^{-1}$.Initial momentum,$p_i = m 	imes u = 0.

Vedclass · Accepted Answer

$3 \,kg \,m \,s^{-1}$

Vedclass · Answer

(B) Mass of the hockey ball,$m = 200 \,g = 0.2 \,kg$.Initial velocity of the hockey ball,$u = 10 \,m \,s^{-1}$.Initial momentum,$p_i = m 	imes u = 0.2 \,kg 	imes 10 \,m \,s^{-1} = 2 \,kg \,m \,s^{-1}$.Since the ball returns along its original path,the final velocity is in the opposite direction,$v = -5 \,m \,s^{-1}$.Final momentum,$p_f = m 	imes v = 0.2 \,kg 	imes (-5 \,m \,s^{-1}) = -1 \,kg \,m \,s^{-1}$.Change in momentum,$\Delta p = p_f - p_i = -1 \,kg \,m \,s^{-1} - 2 \,kg \,m \,s^{-1} = -3 \,kg \,m \,s^{-1}$.The magnitude of the change in momentum is $|\Delta p| = 3 \,kg \,m \,s^{-1}$.

$A$ hockey ball of mass $200 \,g$ travelling at $10 \,m \,s^{-1}$ is struck by a hockey stick so as to return it along its original path with a velocity of $5 \,m \,s^{-1}$. Calculate the magnitude of the change in momentum of the hockey ball due to the force applied by the hockey stick.

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