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Question

(A) Separately: Current $I = \frac{V}{R} = \frac{220 \ V}{22 \ \Omega} = 10 \ A$.$(b)$ In series: Total resistance $R_s = R_1 + R_2 = 22 \ \Omega + 22

Vedclass · Accepted Answer

$10 \ A, 5 \ A, 20 \ A$

Vedclass · Answer

(A) Separately: Current $I = \frac{V}{R} = \frac{220 \ V}{22 \ \Omega} = 10 \ A$.$(b)$ In series: Total resistance $R_s = R_1 + R_2 = 22 \ \Omega + 22 \ \Omega = 44 \ \Omega$.Therefore,current $I = \frac{V}{R_s} = \frac{220 \ V}{44 \ \Omega} = 5 \ A$.$(c)$ In parallel: Total resistance $\frac{1}{R_p} = \frac{1}{R_1} + \frac{1}{R_2} = \frac{1}{22} + \frac{1}{22} = \frac{2}{22} = \frac{1}{11} \ \Omega^{-1}$.Therefore,$R_p = 11 \ \Omega$.Thus,current $I = \frac{V}{R_p} = \frac{220 \ V}{11 \ \Omega} = 20 \ A$.

$A$ hot plate of an electric oven connected to a $220 \ V$ line has two resistors $A$ and $B$ each of $22 \ \Omega$ resistance. These resistors may be used separately,in series,or in parallel. Find the current flowing in all the three cases.

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