A hydrocarbon C_5H_8 consumes two moles of hy | vedclass

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(D) The hydrocarbon $C_5H_8$ consumes $2$ moles of $H_2$,which indicates the presence of two double bonds (a diene). Ozonolysis of $2-$methyl$-1,3-$bu

Vedclass · Accepted Answer

$CH_2=C(CH_3)-CH=CH_2$

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(D) The hydrocarbon $C_5H_8$ consumes $2$ moles of $H_2$,which indicates the presence of two double bonds (a diene). Ozonolysis of $2-$methyl$-1,3-$butadiene $(CH_2=C(CH_3)-CH=CH_2)$ breaks the double bonds to form $HCHO$ (methanal) and $CH_3-CO-CHO$ ($2-$oxopropanal). The reaction is: $CH_2=C(CH_3)-CH=CH_2 \xrightarrow{1. O_3, 2. Zn/H_2O} HCHO + CH_3-CO-CHO + HCHO$.

$A$ hydrocarbon $C_5H_8$ consumes two moles of hydrogen. On ozonolysis,it produces $2-$oxopropanal and methanal. The hydrocarbon is:

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