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(B) The reaction starts with $hex-5-yn-1-ol$. Hydrogenation with $H_2$ (typically over a catalyst like $Pd/BaSO_4$ or similar) reduces the alkyne to a

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Racemic

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(B) The reaction starts with $hex-5-yn-1-ol$. Hydrogenation with $H_2$ (typically over a catalyst like $Pd/BaSO_4$ or similar) reduces the alkyne to an alkene,forming $hex-5-en-1-ol$ (intermediate $A$).In the presence of an acid catalyst $(H^{\oplus})$,the alkene undergoes protonation to form a carbocation at the $C_5$ position. The oxygen atom of the hydroxyl group then attacks this $sp^2$-hybridized carbocation to form a cyclic ether (tetrahydropyran derivative).Since the carbon atom where the ring closure occurs becomes a chiral center and the attack can occur from either face of the planar carbocation,both $R$ and $S$ enantiomers are formed in equal amounts.Therefore,the end product is a racemic mixture.

The end product formed in the above reaction is:

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