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(A) In an electrochemical cell representation,the left side represents the anode (oxidation) and the right side represents the cathode (reduction).Giv

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$A + B^{+} \rightarrow A^{+} + B$

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(A) In an electrochemical cell representation,the left side represents the anode (oxidation) and the right side represents the cathode (reduction).Given cell: $A \,|\, A^{+} \,(x \ M) \, ||\, B^{+} \,(y \ M) \, |\, B$At the anode (left): $A \rightarrow A^{+} + e^-$At the cathode (right): $B^{+} + e^- \rightarrow B$Adding these two half-reactions,the overall cell reaction is: $A + B^{+} \rightarrow A^{+} + B$Since the measured $emf$ is positive $(+ 0.20 \ V)$,the reaction is spontaneous in the direction written.

$A$ hypothetical electrochemical cell is shown below.
$A \,|\, A^{+} \,(x \ M)\, ||\, B^{+} \,(y \ M)\, |\, B$
The $emf$ measured is $+ 0.20 \ V.$ The cell reaction is

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$A$ hypothetical electrochemical cell is shown below.$A \,|\, A^{+} \,(x \ M)\, ||\, B^{+} \,(y \ M)\, |\, B$The $emf$ measured is $+ 0.20 \ V.$ The cell reaction is