A jet plane is travelling towards west at a s | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Speed of the jet plane,$v = 1800\; km/h = 500\; m/s$.Wing span of the jet plane,$l = 25\; m$.Earth's magnetic field strength,$B = 5.0 	imes 10^{-

Vedclass · Accepted Answer

$3.125$

Vedclass · Answer

(A) Speed of the jet plane,$v = 1800\; km/h = 500\; m/s$.Wing span of the jet plane,$l = 25\; m$.Earth's magnetic field strength,$B = 5.0 	imes 10^{-4}\; T$.Angle of dip,$\delta = 30^{\circ}$.The vertical component of the Earth's magnetic field,$B_v = B \sin \delta$.$B_v = 5 	imes 10^{-4} 	imes \sin 30^{\circ} = 5 	imes 10^{-4} 	imes 0.5 = 2.5 	imes 10^{-4}\; T$.The induced electromotive force (voltage difference) between the ends of the wing is given by $e = B_v 	imes l 	imes v$.$e = 2.5 	imes 10^{-4} 	imes 25 	imes 500$.$e = 3.125\; V$.Thus,the voltage difference developed between the ends of the wings is $3.125\; V$.

$A$ jet plane is travelling towards west at a speed of $1800\; km/h$. What is the voltage difference developed between the ends of the wing having a span of $25\; m$,if the Earth's magnetic field at the location has a magnitude of $5 \times 10^{-4}\; T$ and the dip angle is $30^{\circ}$ (in $; V$)?

Similar Questions

If current $I$ is flowing in a closed circuit with total resistance $R$,the rate of production of heat energy in the loop as we pull it with a constant speed $V$ is ($L=$ length of conductor,$B=$ magnetic field).

The loop shown moves with a constant velocity $V$ in a uniform magnetic field of magnetic induction $B$ directed into the paper. The potential difference between $P$ and $Q$ is:

$A$ horizontal straight wire $20 \; m$ long extending from east to west is falling with a speed of $5.0 \; m/s$ at right angles to the horizontal component of the earth's magnetic field $0.30 \times 10^{-4} \; Wb/m^2$. The instantaneous value of the emf induced in the wire will be ......... $mV$.

Consider the situation shown in the figure. The wire $AB$ is sliding on the fixed rails with a constant velocity. If the wire $AB$ is replaced by a semicircular wire,the magnitude of the induced current will

$A$ conducting ring of radius $R$ is placed in a uniform inward magnetic field $\vec B$ as shown. If the ring is moving with velocity $\vec v$ in its plane,the induced $emf$ across the arc $PQ$ will be:

Vedclass Test Series

Exam Paper Generator

Online Exam Module