A linear aperture whose width is 0.02, cm is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given:Width of aperture $a = 0.02\, cm = 2 	imes 10^{-4}\, m$Wavelength $\lambda = 5 	imes 10^{-5}\, cm = 5 	imes 10^{-7}\, m$Focal length of l

Vedclass · Accepted Answer

$0.15$

Vedclass · Answer

(B) Given:Width of aperture $a = 0.02\, cm = 2 	imes 10^{-4}\, m$Wavelength $\lambda = 5 	imes 10^{-5}\, cm = 5 	imes 10^{-7}\, m$Focal length of lens $f = 60\, cm = 0.6\, m$. Since the screen is at the focal plane,the distance $D = f = 0.6\, m$.For Fraunhofer diffraction at a single slit,the condition for the $n^{th}$ dark band (minima) is given by $a \sin 	heta = n\lambda$.For the first dark band,$n = 1$,so $\sin 	heta \approx 	heta = \frac{\lambda}{a}$.The distance from the centre of the screen is $y_1 = D 	heta = \frac{D\lambda}{a}$.Substituting the values:$y_1 = \frac{0.6 	imes 5 	imes 10^{-7}}{2 	imes 10^{-4}} = \frac{3 	imes 10^{-7}}{2 	imes 10^{-4}} = 1.5 	imes 10^{-3}\, m = 0.15\, cm$.

Similar Questions

$A$ wavefront presents one,two and three $HPZ$ at points $A, B$ and $C$ respectively. If the ratio of consecutive amplitudes of $HPZ$ is $4 : 3$,then the ratio of resultant intensities at these points will be

$A$ single slit of width $d$ is illuminated by violet light of wavelength $400 \ nm$ and the width of the diffraction pattern is measured as $Y$. When half of the slit width is covered and illuminated by yellow light of wavelength $600 \ nm$,the width of the diffraction pattern is

The half angular width of the central maxima in the Fraunhofer diffraction due to a slit of width $\frac{1200}{\sqrt{2}} \ \mu m$ is $45^o$. Then the wavelength of the light is ...... $\mu m$.

In a single-slit diffraction experiment,what is the width of the slit $(b)$ such that $20$ maxima of a double-slit interference pattern are obtained within the central maximum of the diffraction pattern? (Given: Slit separation for the double-slit arrangement $d = 2 \, mm$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module