A long solenoid with 1000 , text{turns/m} has | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The magnetic moment $M$ of a core material in a solenoid is given by $M = I_{m} V$, where $I_{m}$ is the intensity of magnetization and $V$ is the

Vedclass · Accepted Answer

$250$

Vedclass · Answer

(D) The magnetic moment $M$ of a core material in a solenoid is given by $M = I_{m} V$, where $I_{m}$ is the intensity of magnetization and $V$ is the volume.$I_{m} = \chi H$, where $\chi$ is the magnetic susceptibility and $H$ is the magnetic field intensity.Since $\chi = \mu_{r} - 1$, we have $M = (\mu_{r} - 1) H V$.For a long solenoid, $H = nI$, which remains constant.Thus, $M \propto (\mu_{r} - 1)$.The fractional change in magnetic moment is $\frac{\Delta M}{M} = \frac{(\mu_{r2} - 1) - (\mu_{r1} - 1)}{\mu_{r1} - 1} = \frac{\mu_{r2} - \mu_{r1}}{\mu_{r1} - 1}$.Given $\mu_{r1} = 500$ and $\mu_{r2} = 750$, we get $\frac{\Delta M}{M} = \frac{750 - 500}{500 - 1} = \frac{250}{499}$.Comparing this with $\frac{x}{499}$, we find $x = 250$.

Similar Questions

In the loop shown,the magnetic induction at the point $O$ is

$A$ long straight wire carries an electric current of $2\,A$. The magnetic induction at a perpendicular distance of $5\,m$ from the wire is

An infinitely long straight conductor is bent into the shape as shown in the figure. It carries a current of $i$ $ampere$ and the radius of the circular loop is $r$ $metre$. Then the magnetic induction at its centre $O$ will be:

$A$ current flows through a circular coil of radius $R$. Find the distance from the center on the axis where the magnetic field is $\frac{1}{8}$th of the magnetic field at the center.

Vedclass Test Series

Exam Paper Generator

Online Exam Module