A loop rolls down on an inclined plane. The f | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For a loop (thin ring) rolling without slipping,the moment of inertia is $I = MR^2$ and the condition for rolling is $v = R\omega$.The rotational

Vedclass · Accepted Answer

$1:2$

Vedclass · Answer

(A) For a loop (thin ring) rolling without slipping,the moment of inertia is $I = MR^2$ and the condition for rolling is $v = R\omega$.The rotational kinetic energy is $K_R = \frac{1}{2} I \omega^2 = \frac{1}{2} (MR^2) \omega^2 = \frac{1}{2} Mv^2$.The translational kinetic energy is $K_T = \frac{1}{2} Mv^2$.The total kinetic energy is $K_{total} = K_R + K_T = \frac{1}{2} Mv^2 + \frac{1}{2} Mv^2 = Mv^2$.The fraction of total kinetic energy associated with rotational motion is $\frac{K_R}{K_{total}} = \frac{\frac{1}{2} Mv^2}{Mv^2} = \frac{1}{2}$.

$A$ loop rolls down on an inclined plane. The fraction of its total kinetic energy that is associated with the rotational motion is

Similar Questions

Two solid spheres of different mass,radii,and density roll down a rough inclined plane under identical situations. Their time to come down is independent of their ............

$A$ thin circular ring first slips down a smooth incline then rolls down a rough incline of identical geometry from the same height. The ratio of the time taken in the two motions is ........

$A$ solid sphere rolls on a surface with a translational velocity $v \ m/s$. It climbs up a curved surface without slipping. The minimum value of $v$ required to reach the height $h$ is:

If a sphere is rolling,the ratio of its rotational energy to the total kinetic energy is given by

Vedclass Test Series

Exam Paper Generator

Online Exam Module