A machine gun can fire 50 , g bullets with a | vedclass

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(A) Given:Mass of bullet $m_{B} = 50 \, g = 50 	imes 10^{-3} \, kg = 0.05 \, kg$.Velocity of bullet $v_{B} = 150 \, m s^{-1}$.Mass of stone $m_{S} =

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$80$

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(A) Given:Mass of bullet $m_{B} = 50 \, g = 50 	imes 10^{-3} \, kg = 0.05 \, kg$.Velocity of bullet $v_{B} = 150 \, m s^{-1}$.Mass of stone $m_{S} = 60 \, kg$.Velocity of stone $v_{S} = 10 \, m s^{-1}$.Let $n$ be the number of bullets required to stop the stone.According to the law of conservation of momentum,the total momentum of the system must be zero to stop the stone.$n(m_{B} v_{B}) + m_{S} v_{S} = 0$.Taking the direction of the stone as positive,the bullets are fired in the opposite direction,so their velocity is negative relative to the stone's motion.$n(0.05 	imes 150) + 60 	imes (-10) = 0$.$n(7.5) = 600$.$n = \frac{600}{7.5} = 80$.Therefore,$80$ bullets must be fired to stop the stone.

$A$ machine gun can fire $50 \, g$ bullets with a velocity of $150 \, m s^{-1}$. $A$ $60 \, kg$ stone is moving towards the machine gun with a velocity of $10 \, m s^{-1}$. How many bullets must be fired from the gun to just stop the stone in its tracks?

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