A machine gun fires a bullet of mass 40, g wi | vedclass

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(D) Given: Mass of bullet $m = 40\, g = 0.04\, kg$,velocity $v = 1200\, m/s$,and maximum force $F = 144\, N$.Let $n$ be the number of bullets fired pe

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$3$

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(D) Given: Mass of bullet $m = 40\, g = 0.04\, kg$,velocity $v = 1200\, m/s$,and maximum force $F = 144\, N$.Let $n$ be the number of bullets fired per second.The force exerted by the man must balance the rate of change of momentum of the bullets.The force $F$ is given by $F = n 	imes (m 	imes v)$.Substituting the values: $144 = n 	imes (0.04\, kg 	imes 1200\, m/s)$.$144 = n 	imes 48$.$n = \frac{144}{48} = 3$.Therefore,the man can fire $3$ bullets per second at the most.

$A$ machine gun fires a bullet of mass $40\, g$ with a velocity $1200\, m/s$. The man holding it can exert a maximum force of $144\, N$ on the gun. How many bullets can he fire per second at the most?

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