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(A) The force on a moving charge in a magnetic field is given by $\overrightarrow{F} = q(\overrightarrow{v} 	imes \overrightarrow{B})$.For the region

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(A) The force on a moving charge in a magnetic field is given by $\overrightarrow{F} = q(\overrightarrow{v} 	imes \overrightarrow{B})$.For the region $a Thus,$\overrightarrow{F} = q(v_0 \hat{i} 	imes B_0 \hat{j}) = q v_0 B_0 \hat{k}$.Since the force is in the $+\hat{k}$ direction,the path will be concave upward.For the region $2a The force $\overrightarrow{F} = q(\overrightarrow{v} 	imes -B_0 \hat{j})$ will now have a component in the $-\hat{k}$ direction.Thus,the path will be concave downward in this region.Comparing this with the given options,the trajectory shown in Option $A$ matches this behavior.

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