A man covers frac{1}{3} of his journey by tra | vedclass

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(C) Let the total distance of the journey be $3d$. Each part of the journey is $d$. Time taken for the first part $t_1 = \frac{d}{80}$. Time taken for

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$48$

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(C) Let the total distance of the journey be $3d$. Each part of the journey is $d$. Time taken for the first part $t_1 = \frac{d}{80}$. Time taken for the second part $t_2 = \frac{d}{60}$. Time taken for the third part $t_3 = \frac{d}{30}$. Total time $T = t_1 + t_2 + t_3 = d(\frac{1}{80} + \frac{1}{60} + \frac{1}{30})$. $T = d(\frac{3 + 4 + 8}{240}) = d(\frac{15}{240}) = \frac{d}{16}$. Average speed $= \frac{	ext{Total distance}}{	ext{Total time}} = \frac{3d}{d/16} = 3 	imes 16 = 48\, km/h$.

$A$ man covers $\frac{1}{3}$ of his journey by train at $80\, km/h$,the next $\frac{1}{3}$ by bus at $60\, km/h$,and the rest by bicycle at $30\, km/h$. Find the average speed of the man during the whole journey (in $km/h$).

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